1附件你好
我用这些代码创建了fibo
插入的代码#include lt; ChartObjects \ ChartObjectsFibo.mqhgt; CChartObjectFibo myFibo;/.... myFibo.Create(0,myFibo,0,Time#91; t1#93;,p1,Time#91; t2#93;,p2);/...是否可以获得它的角度 - 与trendByAngle给出的角度相当?
angle1 = MathArctan((p2-p1)/(t1-t2));
angle2 = MathArctan((p2-p1)/(Time [t2] - Time [t1]));
angle1或angle2给出错误的值(以弧度表示)
谢谢